x^2+(25-3x)/5)^2-4x+6(25-3x)/5)-21=0

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Solution for x^2+(25-3x)/5)^2-4x+6(25-3x)/5)-21=0 equation: 



x^2+(25-3x)/5)^2-4x+6(25-3x)/5)-21=0



Domain of the equation: 5)^2-4x+6(25!=0

x∈R



We add all the numbers together, and all the variables

x^2+(-3x+25)/5)^2-4x+6(-3x+25)/5)-21=0

We add all the numbers together, and all the variables

x^2-3x+(-3x+25)/5)^2-4x+6(+25)/5)-21=0

We calculate fractions


x^2-3x+((-3x+25)*5)-21)/5^2-4x+60-21)+25*5)^2-4x+6()/5^2-4x+60-21)=0



We calculate terms in parentheses: +((-3x+25)*5), so:

(-3x+25)*5

We multiply parentheses

-15x+125

Back to the equation:

+(-15x+125)



We can not solve this equation

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